A silver nugget weighing 30 kg was found. What is the specific heat of silver if 294 kJ

A silver nugget weighing 30 kg was found. What is the specific heat of silver if 294 kJ of energy is released when the nugget is cooled from 80 to 10 ° C?

The amount of thermal energy released when the silver nugget cools:

Q = C * m * ∆t, where Q is the released amount of energy (Q = 294 kJ = 294 * 10³ J), C is the specific heat capacity of silver (J / (kg * K)), m is the mass of the nugget (m = 30 kg), ∆t – temperature change (∆t = tн – tк, where tн – initial temperature (tн = 80 ºС), tк – final temperature (tк = 10 ºС)).

Specific heat of silver:

С = Q / (m * ∆t) = 294 * 10³ / (30 * (80 – 10)) = 140 J / (kg * K).