A spring with a stiffness of 800 was compressed by 5 cm what speed a bullet weighing 10 grams would acquire when fired in a horizontal direction.
The work performed when the spring is compressed with a stiffness k:
A = k x ^ 2/2,
where k is the coefficient of stiffness (or simply stiffness) of the spring; k = 800 N / m;
x is the magnitude of the compression deformation, x = 5 cm = 0.05 m.
A = 800 × 0.05 ^ 2/2 = 1.00 J.
When the spring returns to its original size, work A is equal to the kinetic energy of the bullet attached to the spring:
A = Ek = M V ^ 2/2,
where M is body weight, kg; V – bullet speed, m / s.
V = (2 A / M) ^ 1/2 = (2 × 1.0 / 0.01) ^ 0.5 = 44.72 m / s.
Answer: 44.72 m / s.
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