# A truck moving with constant acceleration On a certain part of the route, it increased its speed from 15 to 25 m / s.

July 23, 2021 | education

| **A truck moving with constant acceleration On a certain part of the route, it increased its speed from 15 to 25 m / s. How long did this increase in speed take place if the acceleration of movement is 1.6 m / s2.**

The speed of a truck with uniformly accelerated movement can be expressed by the formula:

V = V0 + a * t, where V is the final speed of the truck (V = 25 m / s), V0 is the initial speed of the truck (V0 = 15 m / s), and is the acceleration of the truck (a = 1.6 m / s²), t – time of speed increase (s).

Let us express and calculate the time of the increase in speed:

V = V0 + a * t.

a * t = V – V0.

t = (V – V0) / a = (25 – 15) / 1.6 = 6.25 s.

Answer: The increase in the speed of the truck took 6.25 seconds.

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