A vehicle weighing 1 tonne descends the hillside at a constant speed.

A vehicle weighing 1 tonne descends the hillside at a constant speed. The slope is 1 m for every 10 m of the path. Determine the braking force of the vehicle.

m = 1 t = 1000 kg.

g = 10 m / s2.

S = 10 m.

h = 1 m.

Ftorm -?

Since the car moves uniformly in a straight line, then, according to 1 Newton’s law, the action of forces on it is compensated.

m * g + N + Fstorm = 0, where m * g is the force of gravity, N is the surface reaction, Fstorm is the braking force.

ОХ: m * g * sinα – Fstorm = 0.

ОУ: – m * g * cosα + N = 0 /

Ftorm = m * g * sinα.

sinα = h / S.

The braking force Fbrake will be determined by the formula: Fbrake = m * g * h / S.

Ftorm = 1000 kg * 10 m / s2 * 1 m / 10 m = 1000 N.

Answer: the braking force of the car is Ftorm = 1000 N.