A vehicle weighing 1 tonne descends the hillside at a constant speed. The slope is 1 m for every 10 m of the path. Determine the braking force of the vehicle.
m = 1 t = 1000 kg.
g = 10 m / s2.
S = 10 m.
h = 1 m.
Since the car moves uniformly in a straight line, then, according to 1 Newton’s law, the action of forces on it is compensated.
m * g + N + Fstorm = 0, where m * g is the force of gravity, N is the surface reaction, Fstorm is the braking force.
ОХ: m * g * sinα – Fstorm = 0.
ОУ: – m * g * cosα + N = 0 /
Ftorm = m * g * sinα.
sinα = h / S.
The braking force Fbrake will be determined by the formula: Fbrake = m * g * h / S.
Ftorm = 1000 kg * 10 m / s2 * 1 m / 10 m = 1000 N.
Answer: the braking force of the car is Ftorm = 1000 N.
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