A vessel with a volume of 16.64 liters contains 14 g of gas. Gas pressure 75 kPa, temperature 300K. What kind of gas is it?

univerkov | July 26, 2021 | education

Problem data: V (vessel volume) = 16.64 l (in SI V = 0.01664 m3); m (mass of the gas in question) = 14 g; P (pressure) = 75 kPa (75 * 10 ^ 3 Pa); T (absolute temperature) = 300 K.

Constants: R (universal gas constant) = 8.31 J / (mol * K).

The gas in the vessel is determined by the value of its molar mass (Mendeleev-Clapeyron’s law): P * V = m / M * R * T, whence M = m * R * T / (P * V).

Calculation: M = 14 * 8.31 * 300 / (75 * 10 ^ 3 * 0.01664) ≈ 28 g / mol (nitrogen).

Answer: The gas in question is nitrogen.

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