m = 200 grams = 0.2 kilograms – weight of a body suspended on a spring;
g = 10 m / s ^ 2 – acceleration of gravity.
It is required to determine the elastic force acting on the spring Fпр (Newton).
According to Newton’s second law, the body is affected by the downward gravity force and the upward spring force. The force of gravity tends to stretch the spring, and the force of elasticity tries to compress it. Since the body is in balance, then:
Fпр = F gravity;
Fcont = m * g = 0.2 * 10 = 2 Newton.
Answer: the spring force is equal to 2 Newtons.
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