A wire spiral, the resistance of which in a heated state is 55 ohms. Included in a 110 V circuit.
| March 25, 2021 | education
A wire spiral, the resistance of which in a heated state is 55 ohms. Included in a 110 V circuit. How much heat will the coil release in 1 minute?
Task data: R (resistance of the used wire spiral) = 55 Ohm; U (mains voltage) = 110 V; t – operating time (t = 1 min; in SI t = 60 s).
To calculate the amount of heat released by the wire spiral used, we apply the formula: Q = U ^ 2 * t / R.
Calculation: Q = 110 ^ 2 * 60/55 = 13.2 * 10 ^ 3 J (13.2 kJ).
Answer: The spiral wire used will give off 13.2 kJ of heat.
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