A wooden block weighing M = 1.5 kg floats on the surface. What mass m can be put on it so that the bar is completely submerged in the water, and the load is still above the water? Density of wood = 0.8 g / cm3
Data: mb – the mass of the specified wooden block (mb = 1.5 kg); ρд – wood density (ρд = 0.8 g / cm3 = 800 kg / m3).
Const: ρw – water density (approx. Ρw = 10 ^ 3 kg / m3).
To find out the maximum mass of the load placed on the indicated wooden block, consider the equality: Ft = FA.
(mb + mgr) * g = ρw * g * Vbr.
mb + mbr = ρw * mbr / ρd.
mbr = ρw * mbr / ρd – mbr.
mgr = (ρw / ρd – 1) * mbr.
Let’s calculate: mgr = (10 ^ 3/800 – 1) * 1.5 = 0.375 kg.
Answer: The maximum weight of the load placed on the indicated wooden block is 0.375 kg.
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