A wooden block weighing M = 1.5 kg floats on the surface. What mass m can be put on it so that the bar

A wooden block weighing M = 1.5 kg floats on the surface. What mass m can be put on it so that the bar is completely submerged in the water, and the load is still above the water? Density of wood = 0.8 g / cm3

Data: mb – the mass of the specified wooden block (mb = 1.5 kg); ρд – wood density (ρд = 0.8 g / cm3 = 800 kg / m3).

Const: ρw – water density (approx. Ρw = 10 ^ 3 kg / m3).

To find out the maximum mass of the load placed on the indicated wooden block, consider the equality: Ft = FA.

(mb + mgr) * g = ρw * g * Vbr.

mb + mbr = ρw * mbr / ρd.

mbr = ρw * mbr / ρd – mbr.

mgr = (ρw / ρd – 1) * mbr.

Let’s calculate: mgr = (10 ^ 3/800 – 1) * 1.5 = 0.375 kg.

Answer: The maximum weight of the load placed on the indicated wooden block is 0.375 kg.