ABC and A1B1C1 are triangles, AB = A1B1, AC = A1C1, angle A = angle A1.

ABC and A1B1C1 are triangles, AB = A1B1, AC = A1C1, angle A = angle A1. It is known that AC = 12 cm, AB = AC + 3, BC = AC-2 cm.Calculate the perimeter of the triangle A1B1C1.

Since AB = A1B1, AC = A1C1, angle A = angle A1, triangles ABC and A1B1C1 are equal in two

sides and corner between them. So A1C1 = AC; P = P1;

AB = AC + 3 = 12 + 3 = 15 (cm);

BC = AC – 2 = 12 – 2 = 10 (cm);

P = AB + BC + AC = 15 + 10 + 12 = 37 (cm);

Р1 = 37 cm.



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