AC-diagonal of rectangle ABCD, CAD angle = 30 degrees, CD = 10 cm, find the sides of the rectangle

In a right-angled triangle ACD, the leg CD lies opposite an angle of 30, then AC = 2 * CD = 2 * 10 = 20 cm.

By the Pythagorean theorem, AD ^ 2 = AC ^ 2 – BD ^ 2 = 400 – 100 = 30.

AD = 10 * √3 cm.

Answer: The sides of the rectangle are 10 cm and 10 * √3 cm.



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