According to the reaction equation: ZnO + C → CO2 + Zn, calculate the mass of the formed carbon monoxide (IV) if zinc oxide reacted 40.5 g
1.Let’s find the amount of zinc oxide substance by the formula:
n = m: M, where M is molar mass.
M (ZnO) = 65 + 16 = 81 g / mol.
n = 40.5: 81 g / mol = 0.5 mol.
2. Let’s compose the reaction equation, find the quantitative ratios of substances.
2 ZnO + 2C = 2CO2 + 2Zn.
For 2 moles of zinc oxide, there are 2 moles of carbon monoxide. This means they are in a 2: 2 ratio.
The amount of zinc oxide and carbon monoxide substance will be equal.
n (CO2) = 0.5 mol.
3. Find the mass of carbon monoxide.
m = nM,
M (CO2) = 12 + 16 × 2 = 44 g / mol.
m = 0.5 mol × 44 g / mol = 22 g.
Answer: 22 g.
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