# Acetaldehyde weighing 330 g was obtained from 280 liters of acetylene. Calculate the mass fraction of the product yield.

Let’s implement the solution:

1. We write the equation according to the condition of the task:

V = 280 HP m = 330 g; W -?

С2Н2 + Н2О = Н2С = СН – ОН = Н3С – СОН – hydration, vinyl alcohol is released, which undergoes isomerization, acetaldehyde is obtained;

2. Calculations:

M (C2H2) = 26 g / mol;

M (C2H4O) = 44 g / mol.

3. Determine the amount of the original substance:

1 mol of gas at normal level – 22.4 liters;

X mol (C2H2) – 280 liters. hence, X mol (C2H2) = 1 * 280 / 22.4 = 12.5 mol;

Y (C2H4O) = 12.5 mol since the amount of substances according to the equation is 1 mol.

4. Find the mass and yield of the product:

m (C2H4O) = Y * M = 12.5 * 44 = 550 g.

W = m (practical) / m (theoretical) * 100;

W = 330/550 * 100 = 60%.

Answer: the output of acetaldehyde is 60%.