Acetaldehyde weighing 330 g was obtained from 280 liters of acetylene. Calculate the mass fraction of the product yield.

| June 30, 2021 | education

Let’s implement the solution:
1. We write the equation according to the condition of the task:
V = 280 HP m = 330 g; W -?
С2Н2 + Н2О = Н2С = СН – ОН = Н3С – СОН – hydration, vinyl alcohol is released, which undergoes isomerization, acetaldehyde is obtained;
2. Calculations:
M (C2H2) = 26 g / mol;
M (C2H4O) = 44 g / mol.
3. Determine the amount of the original substance:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H2) – 280 liters. hence, X mol (C2H2) = 1 * 280 / 22.4 = 12.5 mol;
Y (C2H4O) = 12.5 mol since the amount of substances according to the equation is 1 mol.
4. Find the mass and yield of the product:
m (C2H4O) = Y * M = 12.5 * 44 = 550 g.
W = m (practical) / m (theoretical) * 100;
W = 330/550 * 100 = 60%.
Answer: the output of acetaldehyde is 60%.



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