AD in trapezoid ABCD of base AD and BC are 6 and 1, respectively, and its area is 42. Find the area of triangle ABCD.
| March 31, 2021 | education
S trapezoid ABCD = (1/2) (AD + BC) h, where h is the height,
h = 2 S trapezoid ABCD: (AD + BC) = 2 42: (6 + 1) = 12, h = 12,
S triangle ABC = (1/2) BC h = (1/2) 1 12 = 6,
Answer: S of triangle ABC = 6.
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