After passing 0.896 l of hydrogen sulfide through the potassium hydroxide solution, 220 g of potassium

After passing 0.896 l of hydrogen sulfide through the potassium hydroxide solution, 220 g of potassium sulfide solution were obtained. Calculate the mass fraction of salt in the resulting solution. Last with solution

2KOH + H2S = K2S + 2H2O

Let’s find the amount of hydrogen sulfide substance:

n (H2S) = V (H2S) / VM = 0.896 / 22.4 = 0.04 mol;

According to the stoichiometry of the reaction:

n (K2S) = n (H2S) = 0.04 mol;

Find the mass of potassium sulfide:

m (K2S) = n (K2S) * M (K2S) = 0.04 * 110 = 4.4 g;

Let’s find the mass fraction of salt:

w (K2S) = m (K2S) / m (solution) = 4.4 / 220 = 0.02 = 2%.

Answer: w (K2S) = 2%.