An arrow fired from the Earth’s surface at an angle of 30 degrees at a speed of 20 m / s rises to a maximum height equal to …?
To find the maximum lift of a given boom, we will use the formula: hmax = V0 ^ 2 * sin2α / 2g.
Constants and variables: V0 – boom launch speed (V0 = 20 m / s); α is the angle between the arrow velocity vector and the Earth’s surface (α = 30º); g – acceleration due to gravity (g ≈ 10 m / s2).
Calculation: hmax = V02 * sin2α / 2g = 20 ^ 2 * sin230º / (2 * 10) = 400 * 0.25 / 20 = 5 m.
Answer: The given arrow will be able to rise to a height of 5 m.
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