An electric current of 1.2A flows through a 25 Ohm resistor for 1.5 minutes.

An electric current of 1.2A flows through a 25 Ohm resistor for 1.5 minutes. Find the amount of heat released in the resistor

Data: R (resistance of a given resistor) = 25 Ohm; I (electric current) = 1.2 A; t (duration of the resistor) = 1.5 min (in SI t = 90 s).

To determine the amount of heat released on a given resistor, we apply the formula: Q = I2 * R * t.

Let’s perform the calculation: Q = 1.22 * 25 * 90 = 3.24 * 10 ^ 3 J (3.24 kJ).

Answer: In 1.5 minutes, 3.24 kJ of heat was released on a given conductor.



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