An electric lamp consumes 36 kW of energy in 10 minutes, calculate the voltage on the lamp if the current in it is 0.5 A.
t = 10 min = 600 s.
N1 = 36 kW = 36,000 watts.
I = 0.5 A.
N = U * I – lamp power is determined by the formula.
U = N / I.
Since the lamp consumes N1 energy in 600 s, then N = N1 / t,
U = N1 / t / I = N1 / t * I.
U = 36,000 W / 600 s * 0.5 A = 120 V.
Answer: the voltage in the lamp is U = 120 V.
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