An ice floe floats in the water, a part of which with a volume of 200 m3 is above the water. What is the volume of the entire ice floe, if the density of ice is 900kg / m3, and the density of water is 1000kg / m3
According to Archimedes’ law, the mass of a floating ice floe should be equal to the mass of water in the volume of a part of the ice floe that is under water.
Multiplying the density of the water by the volume of the submerged part of the ice floe, we find the total mass of the ice floe:
1000 * 200 = 200000 kg.
The volume of the ice floe is equal to the quotient of dividing its mass by the density of the ice:
200000/900 = 222.2 m3.
Answer: 222.2 m3.
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