An iron nail was heated in the air. How much dm3 of xylogen was involved in the reaction, if 0.29 g of oxide was formed. 3Fe + 2O2 = Fe3O4
Let us determine the amount of the substance of the formed iron oxide n (o) = m (o) / M (o), where m (o) and M (o) are the mass and molar mass of iron oxide, respectively.
n (o) = 0.29 / 232 = 0.00125 mol
According to the reaction equation, it can be seen that the formation of such an amount of iron oxide requires 2 times more mol of oxygen, then the amount of oxygen substance n (k) = n (o) * 2 = 0.00125 * 2 = 0.0025 mol
Let us find the required volume of oxygen under normal conditions V (k) = Vm * n (k), where Vm is the molar volume.
V (c) = 0.0025 * 22.4 = 0.056 dm3
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