Angle ABE = 112 degrees Angle DCF = 68 degrees AC-9 cm Find side AB of triangle ABC.

The solution of the problem:
The corners FAE and FAC are adjacent corners. The sum of adjacent angles is 180 degrees.
Therefore, FAE + FAC = 180 degrees.
Let’s substitute the values we know:
112 degrees + FAC angle = 180 degrees.
FAC angle = 180 – 112 = 68 degrees.
Angles DBF and ABC are vertical. The vertical angles are equal.
Therefore, the angle DBF = ABC = 68 degrees.
Consider a triangle ABC:
Angle B and Angle A are 68 degrees.
It turns out that triangle ABC is isosceles.
So side AC = side BC = 9
Problem answer: side AB is 9.

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