As a result of acetylene trimerization with a volume of 4.032 liters, benzene with a mass of 3.74 g was formed. Calculate the practical yield of benzene from the theoretically possible one.
From the reaction equation:
3С₂Н₂ = С₆Н₆.
find the number of moles of acetylene:
n (С₂Н₂) = V / Vm = 4.032 / 22.4 = 0.18 mol.
It can be seen from the equation that the amount of benzene obtained is three times less than acetylene, therefore:
n (С₆Н₆) = 0.18 / 3 = 0.06 mol.
Knowing the molar mass of benzene 78 g / mol, we find the theoretical mass.
m (С₆Н₆) = Mr × n = 78 × 0.06 = 4.68 g.
The practical benzene yield from the theoretical will be equal to:
W (С₆Н₆) = (mprac / mtheor) × 100% = (3.74 / 4.68) × 100% = 80%.
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