As a result of the interaction of acetic acid weighing 90 g with methanol, 100 g of an ester is formed

As a result of the interaction of acetic acid weighing 90 g with methanol, 100 g of an ester is formed, calculate the mass fraction of the yield of the ester

Let’s write the equation:
CH3COOH + CH3 – OH = CH3COO – CH3 + H2O – methyl acetate was obtained;
Let’s make the calculations:
M (CH3COOH) = 60 g / mol;
M (ether) = 74 g / mol;
Let’s calculate the number of moles of acetic acid, ester:
Y (CH3COOH) = m / M = 90/60 = 1.5 mol;
According to the reaction equation, the number of moles of acetic acid and ether are equal to 1 mole, which means that Y (ether) = 1.5 mole;
Let’s determine the mass of the ether according to the equation (theoretical):
m (theoretical) = Y * M = 1.5 * 74 = 111 g;
Let’s calculate the mass fraction of the ether output:
W = m (practical) / m (theoretical) * 100;
W = 100/111 * 100 = 90.09%.
Answer: the ether yield is 90.09%.



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