As a result of the reaction between hydrogen and nitrogen, 18 grams of ammonia was formed. find the masses of the gases that have reacted.
To solve the problem, we compose the equation:
X g -? X g -? m = 18 g.
1. 3H2 + N2 = 2NH3 – compounds, obtained ammonia;
2. Calculations by formulas:
M (H2) = 2 g / mol;
M (N2) = 28 g / mol;
M (NH3) = 17 g / mol;
Y (NH3) = m / M = 18/17 = 1.06 mol.
X mol (H2) – 1.06 mol (NH3);
-3 mol -2 mol hence, X mol (H2) = 3 * 1.06 / 2 = 1.59 mol;
X mol (N2) – 1.06 mol (NH3);
-1 mol – 2 mol hence, X mol (N2) = 1 * 1.06 / 2 = 0.53 mol.
4. Find the masses of the starting materials:
m (H2) = Y * M = 2 * 1.59 = 3.18 g;
m (N2) = Y * M = 0.53 * 28 = 14.84 g.
Answer: the mass of hydrogen is 3.18 g, nitrogen – 14.84 g.
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