At a current strength of 0.5 A, 2.5 * 10 ^ 18 electrons pass through the cross section
| July 23, 2021 | education
At a current strength of 0.5 A, 2.5 * 10 ^ 18 electrons pass through the cross section of the metal conductor. During what time the electrons moved.
I = 0.5 A.
N = 2.5 * 10 ^ 18.
q = 1.6 * 10 ^ -19 Cl.
t -?
The strength of the current I is a scalar physical quantity equal to the ratio of the charge Q, which passed through the cross-section of the conductor, to the time of its passage t: I = Q / t.
Since the charge of one electron is q = 1.6 * 10 ^ -19 C, then Q = q * N.
I = q * N / t.
The transit time of electrons through the conductor will be determined by the formula: t = q * N / I.
t = 1.6 * 10 ^ -19 C * 2.5 * 10 ^ 18 / 0.5 A = 80 s.
Answer: the time for electrons to travel along the conductor is t = 80 s.
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