At a distance of 1 m from the point charge, the electrostatic field strength

At a distance of 1 m from the point charge, the electrostatic field strength is 900 V / m. Determine the amount of charge (in nC) that creates this field?

Initial data: r (distance from the chiseled charge) = 1 m; E (the value of the electric field strength at a distance r from the point charge) = 900 V / m.

Reference data: k (proportionality coefficient, air) = 9 * 10 ^ 9 N * m ^ 2 / Kl ^ 2.

The amount of charge is determined from the following formula: E = k * q / r ^ 2, whence q = E * r ^ 2 / k.

Let’s perform the calculation: q = 900 * 1 ^ 2 / (9 * 10 ^ 9) = 100 * 10 ^ -9 C = 100 nC.

Answer: The amount of charge is 100 nC.