# At a distance of 10 cm from the charged ball, the force F = 1.5 * 10 ^ -2 H acts on the charge q = 10 ^ -9 C.

March 25, 2021 | education

| **At a distance of 10 cm from the charged ball, the force F = 1.5 * 10 ^ -2 H acts on the charge q = 10 ^ -9 C. Find the field strength at this point and determine the ball’s charge.**

Data: r (distance between charge and charged ball) = 10 cm (0.1 m); q2 (considered charge) = 10 ^ -9 C; F (acting force) = 1.5 * 10 ^ -2 N.

Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2.

1) Calculate the charge of the ball: F = k * q1 * q2 / r ^ 2, whence q1 = F * r ^ 2 / (k * q ^ 2) = 1.5 * 10 ^ -2 * 0.1 ^ 2 / (9 * 10 ^ 9 * 10 ^ -9) = 1.67 * 10 ^ -5 Cl.

2) Find the field strength at a point located at a distance of 10 cm from the charged ball: E = F / q1 = 1.5 * 10 ^ -2 / (1.67 * 10 ^ -5) = 898.2 V / m.

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