At a pressure of 0.98 * 10 ^ 5 Pa and a temperature of 150C, the volume of air is 2 liters.

At a pressure of 0.98 * 10 ^ 5 Pa and a temperature of 150C, the volume of air is 2 liters. At what pressure will the air take up a volume of 4 liters, if its temperature becomes 200C.

Data: P1 (initial pressure) = 0.98 * 10 ^ 5 Pa; T1 (initial temperature) = 150 ºС (absolute temperature T1 = 423 K); V1 (initial air volume) = 2 liters (in SI V1 = 2 * 10 ^ -3 m3); V2 (the volume that the air should take) = 4 liters (in SI V2 = 4 * 10 ^ -3 m3); T2 (end temperature) = 200 ºС (absolute temperature T2 = 473 K).

Let us express the final pressure: P1 * V1 / T1 = P2 * V2 / T2, whence P2 = P1 * V1 * T2 / (T1 * V2).

Calculation: P2 = 0.98 * 10 ^ 5 * 2 * 10 ^ -3 * 473 / (423 * 4 * 10 ^ -3) = 0.548 * 105 Pa.