At a voltage of 100 V, the current in the circuit is 10 A. In this circuit, all resistors have the same resistance

At a voltage of 100 V, the current in the circuit is 10 A. In this circuit, all resistors have the same resistance and are connected in parallel. Choose a possible combination of the number of resistors and their resistance, suitable for the given circuit: a. 10 resistors of 4 ohms. 4 resistors 10 Ohm each. 8 resistors 80 Ohm each. 80 resistors of 10 ohms.

Given:

U = 100 Volts – electrical circuit voltage;

I = 10 Amperes – the strength of the current passing through the electrical circuit.

It is required to determine the number n and the size of the resistances R (Ohm), taking into account that they are connected in parallel.

Let’s find the total resistance of the circuit:

R1 = U / I = 100/10 = 10 ohms.

Then, given that they are connected in parallel:

1 / R1 = 1 / R + 1 / R + … + 1 / R.

1 / R1 = (1 + 1 + …. 1) / R;

1 / R1 = n / R, (where n is the total number of resistances);

R = n * R1;

R / n = R1;

R / n = 10.

Substituting all these options, we get that the condition R / n = 10 corresponds to 8 resistors of 80 Ohm, since 80/8 = 10.

Answer: 8 resistors of 80 ohms.