At the end of the arm, forces of 4H and 20H act. The lever arm to low force is 60cm. Define the lever arm for more force when the lever is in balance?
F1 = 4 N.
F2 = 20 N.
L1 = 60 cm = 0.6 m.
When the lever is in equilibrium, the moments of forces that act from opposite sides of the lever are equal to each other: M1 = M2.
The moment of force M is called the product of the applied force F to the smallest distance from the application of force in the axis of rotation of the lever L: M = F * L.
F1 * L1 = F2 * L2.
Let us express the shoulder of greater force L2 by the formula: L2 = F1 * L1 / F2.
L2 = 4 N * 0.6 m / 20 N = 0.12 m.
Answer: in equilibrium, the lever arm of the greater force is L2 = 0.12 m.
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