At what acceleration will the rope break, the breaking strength of which is 15kN, when lifting a load weighing 500kg?

Initial data: ϭ (tensile strength of the considered cable to break) = P (maximum weight that the cable can withstand) = 15 kN (15 * 10 ^ 3 N); m (mass of the load lifted on the cable) = 500 kg.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The acceleration of the load at which the cable breaks can be expressed from the formula: P = m * (g + a) and a = P / m – g.

Calculation: a = 15 * 10 ^ 3/500 – 10 = 30 – 10 = 20 m / s2.

Answer: The rope will break when lifting a load with an acceleration of 20 m / s2.