# At what distance are two point charges in kerosene 4 • 10 ^ -6 C and 2 • 10 ^ -5 C

At what distance are two point charges in kerosene 4 • 10 ^ -6 C and 2 • 10 ^ -5 C, if they interact with a force of 4H? dielectric constant of kerosene 2.1.

Data: q1 (first point charge) = 4 * 10 ^ -6 C; q2 (second point charge) = 2 * 10 ^ -5 C; F (force of interaction of point charges) = 4 N.

Constants: k (proportionality coefficient) = 9 * 10 ^ 9 N * m2 / Cl2; by condition ε (relative dielectric constant of kerosene) = 2.1.

The distance at which the charges are in kerosene can be expressed from the formula: F = k * q1 * q2 / (ε * r ^ 2), whence r = √ (k * q1 * q2 / (F * ε)).

Calculation: r = √ (9 * 10 ^ 9 * 4 * 10 ^ -6 * 2 * 10 ^ -5 / (4 * 2.1)) ≈ 0.293 m (29.3 cm).

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