At what distance from the surface of the Earth will the force of attraction of the spacecraft

At what distance from the surface of the Earth will the force of attraction of the spacecraft to it become 100 times less than on the surface of the Earth?

F1 = 100 * F2.
Rz = 6371 km.
H -?
According to the law of universal gravitation, the force of gravitational attraction is determined by the formula: F = G * m * M / R ^ 2, where G is the gravitational constant, m, M is the mass of interacting bodies, R is the distance between them.
The force of attraction of the spacecraft on the surface of the earth will be determined by the formula: F1 = G * m * M / Rz ^ 2, where Rz is the radius of the earth.
The gravitational force of the spacecraft at a height H above the earth’s surface will be determined by the formula: F2 = G * m * M / R ^ 2.
Where R is the distance from the center of the earth to the spacecraft.
R = Rz + H.
F1 / F2 = G * m * M / R3 ^ 2: G * m * M / R ^ 2 = R ^ 2 / R3 ^ 2.
R ^ 2 / R3 ^ 2 = 100.
R = √ (100 * Rz ^ 2) = 10 * Rz.
Rz + H = 10 * Rz.
H = 10 * Rz – Rz = 9 * Rz.
H = 9 * 6371 km = 57339 km.
Answer: at an altitude of H = 57339 km, the force of attraction of the spacecraft to the earth will be 100 times less.