At what temperature is the gas if the volume increased 1.5 times during its isobaric heating by 200 K?
| July 23, 2021 | education
Initial data: isobaric heating (P (pressure) = const); the gas was heated to 200 K (T2 = T1 + 200); the gas volume increased by 1.5 times (V2 = 1.5V1).
With isobaric heating, the equality is true: V1 / T1 = V2 / T2 and T1 = V1 * T2 / V2 = V1 * (T1 + 200) / 1.5V1 = (T1 + 200) / 1.5.
1.5T1 = 200 + T1.
1.5T1 – T1 = 200.
0.5T1 = 200.
T1 = 200 / 0.5 = 400 K.
Answer: Before isobaric heating, the gas was at a temperature of 400 K.
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