At what value of k is the straight line: y = kx -3 passes through point A (-2; 9).

1. Coordinates of point A (-2; 9):

The abscissa of the point is x = -2;
The ordinate of the point is y = 9.
2. Substitute the coordinates of a given point into the equation of a straight line and solve the resulting equation for k:

y = kx – 3;
9 = k * (-2) – 3;
9 = -2k – 3;
2k = -9 – 3;
2k = -12;
k = -12: 2;
k = -6.
Answer. When the parameter value is k = -6.