Balls with a mass of 600 g and 900 g collide. What acceleration will the second ball receive if the acceleration of the second ball is 0.2 m / s2? In the solution, acceleration is put into the law of conservation of momentum instead of speed, so is it possible?
m1 = 600 g = 0.6 kg.
m2 = 900 g = 0.9 kg.
a2 = 0.2 m / s2.
According to Newton’s 3 law: the force F12, with which the first body acts on the second, is oppositely directed and is equal in magnitude to the force F21 with which the second body acts on the first: F12 = – F21.
The “-” sign indicates that the forces F12 and F21 are oppositely directed.
According to Newton’s 2 law, the force F, which acts on a body, is equal to the product of the body’s mass m by its acceleration a: F = m * a.
F12 = m2 * a2, F21 = m1 * a1.
m2 * a2 = m1 * a1.
a1 = m2 * a2 / m1.
a1 = 0.9 kg * 0.2 m / s2 / 0.6 kg = 0.3 m / s2.
Answer: the acceleration of the first ball will become a1 = 0.3 m / s2.
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