Benzene weighing 11.7 g was combined with 11.2 liters of chlorine. Find the mass of the product

Benzene weighing 11.7 g was combined with 11.2 liters of chlorine. Find the mass of the product if the reaction proceeds without light

Let’s carry out the solution, compose the reaction equation:
1. С6Н6 + Cl2 = C6H5Cl + HCl – the substitution reaction takes place in the presence of the catalyst AlCl3. Benzene chloride was obtained.
2. Let’s make calculations using the formulas:
M (C6H6) = 78 g / mol;
M (C6H5Cl) = 112.5 g / mol;
3. Let’s calculate the amount of moles of benzene, chlorine:
Y (C6H6) = m / M = 11.7 / 78 = 0.15 mol (deficient substance);
Y (Cl2) = V (Cl2) / V g / l = 11.2 / 22.4 = 0.5 mol (substance in excess);
Calculations are made for the substance in deficiency.
4. Let’s make the proportion:
0.15 mol (C6H6) – X mol (C6H5Cl);
-1 mol -1 mol hence, x mol (C6H5Cl) = 0.15 * 1/1 = 0.15 mol.
5. Find the mass of benzene chloride by the formula:
m (C6H5Cl) = Y * M = 0.15 * 112.5 = 16.87 g.
Answer: The mass of benzene chloride is 16.87 g.