# Body weight 1.2 kg. When fully immersed in water, an Archimedes force equal to 2N acts on it.

August 30, 2021 | education

| **Body weight 1.2 kg. When fully immersed in water, an Archimedes force equal to 2N acts on it. Determine the density of the body.**

Given:

m = 1.2 kilograms is the mass of a certain body;

F = 2 Newton – Archimedean (buoyancy) force acting on this body when it is immersed in water;

ro = 1000 kg / m3 is the density of pure water.

It is required to determine ro1 (kg / m3) – body density.

Let’s find the volume of this body:

F = ro * V * g (where g = 10 Newton / kilogram is an approximate value);

V = F / (ro * g) = 2 / (1000 * 10) = 2/10000 = 0.0002 m3.

Then, to determine the density, you must use the following formula:

m = ro1 * V;

ro1 = m / V = 1.2 / 0.0002 = 6000 kg / m3.

Answer: the density of the body is 6000 kg / m3.

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