Body weight 1.2 kg. When fully immersed in water, an Archimedes force equal to 2N acts on it.

Body weight 1.2 kg. When fully immersed in water, an Archimedes force equal to 2N acts on it. Determine the density of the body.

Given:

m = 1.2 kilograms is the mass of a certain body;

F = 2 Newton – Archimedean (buoyancy) force acting on this body when it is immersed in water;

ro = 1000 kg / m3 is the density of pure water.

It is required to determine ro1 (kg / m3) – body density.

Let’s find the volume of this body:

F = ro * V * g (where g = 10 Newton / kilogram is an approximate value);

V = F / (ro * g) = 2 / (1000 * 10) = 2/10000 = 0.0002 m3.

Then, to determine the density, you must use the following formula:

m = ro1 * V;

ro1 = m / V = 1.2 / 0.0002 = 6000 kg / m3.

Answer: the density of the body is 6000 kg / m3.