Body weight 120N. The displaced liquid weight is 100N. Find Archimedean strength.

Initial data: P (weight of the considered body) = 120 N; Pw (weight of the displaced liquid by the body in question) = 100 N.

Since, according to Archimedes’ law, a buoyant force acts on the body under consideration in a liquid, which is equal to the weight of the liquid displaced by it, the sought Archimedes force is equal to 100 N (Fa = Pzh = 100 N).

Answer: The required Archimedean force is 100 N.

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