By conducting a chemical analysis of water, it was determined that the element phosphorus was found
By conducting a chemical analysis of water, it was determined that the element phosphorus was found in the form of PO4. To reduce the concentration of phosphorus, it was treated with Ca (OH) 2 or Al2 (SO4) 3. Write equations for transformations
We will assume that the PO4 ^ (3-) ions in water were formed as a result of the dissolution of sodium phosphate – Na3PO4.
Let’s write down the reaction equations:
1) Na3PO4 + Ca (OH) 2 = NaOH + Ca3 (PO4) 2, calcium phosphate (Ca3 (PO4) 2) will precipitate
Let’s arrange the coefficients:
2 Na3PO4 + 3 Ca (OH) 2 = 6 NaOH + Ca3 (PO4) 2
We write down the ionic equations:
6 Na ^ (+) + 2 PO4 ^ (3-) + 3 Ca ^ (2+) + 6OH ^ (-) = 6 Na ^ (+) + 6OH ^ (-) + Ca3 (PO4) 2
2 PO4 ^ (3-) + 3 Ca ^ (2+) = Ca3 (PO4) 2
2) Na3PO4 + Al2 (SO4) 3 = Na2SO4 + AlPO4, aluminum phosphate (AlPO4) will precipitate.
Let’s arrange the coefficients:
2 Na3PO4 + Al2 (SO4) 3 = 3 Na2SO4 + 2 AlPO4
We write down the ionic equations:
6 Na ^ (+) + 2PO4 ^ (3-) + 2 Al ^ (3+) + 3SO4 ^ (2-) = 6 Na ^ (+) + 3SO4 ^ (2-) + 2 AlPO4
2PO4 ^ (3-) + 2 Al ^ (3+) = 2 AlPO4
PO4 ^ (3-) + Al ^ (3+) = AlPO4