By distilling liquid air, 200 liters of oxygen were obtained. How much nitrogen did you get?

univerkov | June 30, 2021 | education

Knowing that air contains 21% oxygen and 78% nitrogen, we will find the total volume of gases.
V (gases) = V (O2) / W (O2) • 100% = 200 l / 21% • 100% = 952.4 l.
The volume of nitrogen in this mixture is.
V (N2) = V (gases) • W (N2) / 100% = 952.4 liters • 78% / 100% = 952.4 liters.

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