Calcium carbide weighing 16 g was dissolved in water. The volume of gas released in this case amounted to …

According to the condition of the problem, we write down the reaction equation:
CaC2 + 2H2O = C2H2 + Ca (OH) 2 – hydration of calcium carbide, acetylene obtained;
Let’s calculate the molar masses of substances:
M (CaC2) = 40 + 12 * 2 = 64 g / mol;
M (C2H2) = 12 * 2 + 1 * 2 = 26 g / mol;
Determine the amount of moles of calcium carbide by the formula:
Y (CaC2) = m / M = 16/64 = 0.25 mol;
Let’s make the proportion:
0.25 mol (CaC2) – X mol (C2H2);
-1 mol -1 mol hence, X mol (C2H2) = 0.25 * 1/1 = 0.25 mol;
Find the volume of acetylene by applying Avogadro’s law:
V (C2H2) = 0.25 * 22.4 = 5.6 liters.
Answer: the volume of acetylene is 5.6 liters.



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