# Calculate how many liters of hydrogen will be released when 130 grams of zinc interacts with acetic acid.

July 25, 2021 | education

| When dissolved in acetic acid, metallic zinc is converted to zinc acetate. The reaction is described by the following chemical reaction equation:

Zn + 2CH3COOH = Zn (CH3COO) 2 + H2;

Let’s find the chemical amount of zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 130/65 = 2 mol;

With this amount of zinc, 2 x 2 = 4 mol of acid reacts. This will synthesize 2 mol of hydrogen. Let’s calculate its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;

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