Calculate how many liters of hydrogen will be released when 130 grams of zinc interacts with acetic acid.

When dissolved in acetic acid, metallic zinc is converted to zinc acetate. The reaction is described by the following chemical reaction equation:

Zn + 2CH3COOH = Zn (CH3COO) 2 + H2;

Let’s find the chemical amount of zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 130/65 = 2 mol;

With this amount of zinc, 2 x 2 = 4 mol of acid reacts. This will synthesize 2 mol of hydrogen. Let’s calculate its volume. To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 2 x 22.4 = 44.8 liters;



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