Calculate how much of the aluminum substance was dissolved in hydrochloric acid if 67.2 liters

Calculate how much of the aluminum substance was dissolved in hydrochloric acid if 67.2 liters of hydrogen were released under normal conditions. The second product of the reaction is aluminum chloride

The reaction of dissolution of aluminum in hydrochloric acid is described by the following chemical reaction equation:

Al + 3HCl = AlCl3 + 3 / 2H2;

When 1 mol of metal is dissolved, 1.5 mol of hydrogen gas is synthesized.

Let’s calculate the amount of substance contained in 67.2 liters of hydrogen.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N H2 = 67.2 / 22.4 = 3 mol;

To obtain such an amount of hydrogen, it is required to take 3 / 1.5 = 1.0 mol of metallic aluminum.