Calculate the amount of potassium sulfate substance obtained by merging solutions containing 20 mol of sulfuric
Calculate the amount of potassium sulfate substance obtained by merging solutions containing 20 mol of sulfuric acid and 60 mol of potassium hydroxide, preferably with a solution.
Let’s execute the solution:
1. We compose the equation according to the condition:
Y = 20 mol Y = 60 mol X mol -?
H2SO4 + 2KOH = K2SO4 + 2H2O – ion exchange, potassium sulfate, water was formed;
2. Calculations:
M (H2SO4) = 98 g / mol;
M (KOH) = 56.1 g / mol;
M (K2SO4) = 174.2 g / mol.
3. The amount of starting materials:
Y (H2SO4) = 20 mol (deficient substance);
Y (KOH) = 60 mol (substance in excess).
Calculations are made for the substance in deficiency.
Y (K2SO4) = 20 mol since according to the equation the number of moles of acid and base is 1 mol.
Answer: The amount of potassium sulfate product is 20 mol.