# Calculate the amount of potassium sulfate substance obtained by merging solutions containing 20 mol of sulfuric

**Calculate the amount of potassium sulfate substance obtained by merging solutions containing 20 mol of sulfuric acid and 60 mol of potassium hydroxide, preferably with a solution.**

Let’s execute the solution:

1. We compose the equation according to the condition:

Y = 20 mol Y = 60 mol X mol -?

H2SO4 + 2KOH = K2SO4 + 2H2O – ion exchange, potassium sulfate, water was formed;

2. Calculations:

M (H2SO4) = 98 g / mol;

M (KOH) = 56.1 g / mol;

M (K2SO4) = 174.2 g / mol.

3. The amount of starting materials:

Y (H2SO4) = 20 mol (deficient substance);

Y (KOH) = 60 mol (substance in excess).

Calculations are made for the substance in deficiency.

Y (K2SO4) = 20 mol since according to the equation the number of moles of acid and base is 1 mol.

Answer: The amount of potassium sulfate product is 20 mol.