Calculate the amount of potassium sulfate substance obtained by merging solutions containing 20 mol of sulfuric acid and 60 mol of potassium hydroxide, preferably with a solution.
Let’s execute the solution:
1. We compose the equation according to the condition:
Y = 20 mol Y = 60 mol X mol -?
H2SO4 + 2KOH = K2SO4 + 2H2O – ion exchange, potassium sulfate, water was formed;
M (H2SO4) = 98 g / mol;
M (KOH) = 56.1 g / mol;
M (K2SO4) = 174.2 g / mol.
3. The amount of starting materials:
Y (H2SO4) = 20 mol (deficient substance);
Y (KOH) = 60 mol (substance in excess).
Calculations are made for the substance in deficiency.
Y (K2SO4) = 20 mol since according to the equation the number of moles of acid and base is 1 mol.
Answer: The amount of potassium sulfate product is 20 mol.
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