Calculate the amount of salt substance formed when 67.2 liters of hydrogen chloride are drained through a potassium hydroxide solution.
Let’s implement the solution:
1. We write down the equation according to the problem statement:
Y mole -? V = 67.2 l;
KOH + HCl = KCl + H2O – ion exchange, obtained potassium chloride, water;
1 mol 1 mol 1 mol.
2. We make calculations:
M (KOH) = 56.1 g / mol;
M (HCl) = 36.6 g / mol.
1 mole of gas at normal level – 22.4 liters;
X mol (HCl) – 67.2 hence, X mol (HCl) = 1 * 67.2 / 22.4 = 3 mol;
Y (KOH) = 3 mol since the amount of these substances according to the equation is 1 mol.
Answer: to carry out the reaction, you need potassium hydroxide in the amount of 3 mol.
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