Calculate the amount of salt substance formed when 67.2 liters of hydrogen chloride are drained

Calculate the amount of salt substance formed when 67.2 liters of hydrogen chloride are drained through a potassium hydroxide solution.

Let’s implement the solution:
1. We write down the equation according to the problem statement:
Y mole -? V = 67.2 l;
KOH + HCl = KCl + H2O – ion exchange, obtained potassium chloride, water;
1 mol 1 mol 1 mol.
2. We make calculations:
M (KOH) = 56.1 g / mol;
M (HCl) = 36.6 g / mol.
3. Proportion:
1 mole of gas at normal level – 22.4 liters;
X mol (HCl) – 67.2 hence, X mol (HCl) = 1 * 67.2 / 22.4 = 3 mol;
Y (KOH) = 3 mol since the amount of these substances according to the equation is 1 mol.
Answer: to carry out the reaction, you need potassium hydroxide in the amount of 3 mol.



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