# Calculate the amount of substance and the mass of alkali, which was obtained by the interaction

Calculate the amount of substance and the mass of alkali, which was obtained by the interaction of 620 g of sodium oxide and water.

The reaction of sodium oxide and water is described by the following chemical equation:

Na2O + H2O = 2NaOH;

From one mole of sodium oxide, two moles of sodium hydroxide are formed.

Let’s determine the amount of substance in 620 grams of sodium oxide.

Its molar mass is:

M Na2O = 23 x 2 + 16 = 62 grams / mol.

The amount of the substance will be:

N Na2O = 620/62 = 10 mol.

From this amount, 20 moles of alkali can be obtained.

Let’s define its mass:

Its molar mass is:

M NaOH = 23 + 16 + 1 = 40 grams / mol.

The mass will be:

m NaOH = 20 x 40 = 800 grams.

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