# Calculate the amount of substance and the mass of hydrogen chloride formed

Calculate the amount of substance and the mass of hydrogen chloride formed by the reaction of hydrogen with chlorine in a volume of 44.8 liters.

1. Let’s compose the equation of the chemical reaction:

H2 + Cl2 = 2HCl.

2. Find the chemical amount of reacted chlorine (Vm – molar volume, constant equal to 22.4 l / mol):

n (Cl2) = V (Cl2) / Vm = 44.8 L / 22.4 L / mol = 2 mol.

3. According to the reaction equation, we find the chemical amount, and then the mass of the released hydrogen chloride:

n (HCl) = n (Cl2) * 2 = 2 mol * 2 = 4 mol.

m (HCl) = n (HCl) * M (HCl) = 4 mol * 36.5 g / mol = 146 g.

Answer: n (HCl) = 4 mol; m (HCl) = 146 g. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.