Let us raise the equation of the function to the 1/2 power:
y = x ^ (3/2).
Then the area of the figure S formed by the given lines will be equal to the integral:
S = ∫x ^ (3/2) * dx | 0; 4/3 = 2/5 * x ^ (5/2) | 0; 4/3 = 2/5 * (4/3) ^ (5/2) = 2/5 * (2 / √3) ^ 5 = 64/5 (√3) ^ 5.
Answer: the required area is 64/5 (√3) ^ 5.
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