# Calculate the mass and volume of H2 released during the interaction of 4g Ca with HCl?

Explanation of the solution to the problem: in order to solve this problem, it is first necessary to draw up the equation of the chemical reaction: Ca + 2HCl => CaCl2 + H2.
Then you need to find the amount of calcium substance, for this you need to divide its mass by its molar mass:
n (Ca) = m / M = 4/40 = 0.1 mol.
Now you need to find the amount of hydrogen, it is equal to the amount of calcium, because the reaction shows that they interact in a 1: 1 ratio:
n (H2) = n (Ca) = 0.1 mol.
The last step is to find the mass of hydrogen, for this we multiply the found amount of the substance by its molar mass and volume, multiplying the amount of the substance by the molar volume:
m (H2) = n (H2) * M = 0.1 * 2 = 0.2 g.
V (H2) = n (H2) * Vm = 0.1 * 22.4 = 2.24 liters. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.