# Calculate the mass and volume of sulfur (IV) oxide produced by burning 68 g of H2S.

Given:

m (H2S) = 68 g

Find:

m (SO2) -?

V (SO2) -?

Solution:

2H2S + 3O2 = 2H2O + 2SO2, – we solve the problem, relying on the composed reaction equation:

1) Find the amount of hydrogen sulfide that has reacted:

n (H2S) = m: M = 68 g: 34 g / mol = 2 mol

2) We compose a logical expression:

If 2 mol H2S gives 2 mol SO2,

then 2 moles of H2S will give x moles of SO2, is a tautology, but sometimes calculations lead to such results.

then x = 2 mol.

3) Find the mass of sulfur oxide released during the reaction:

m (SO2) = n * M = 2 mol * 64 g / mol = 128 g

4) find the volume of sulfur oxide:

V (SO2) = n * Vm = 2 mol * 22.4 l / mol = 44.8 l.

Answer: m (SO2) = 128 g; V (SO2) = 44.8 liters. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.