m (H2S) = 68 g
m (SO2) -?
V (SO2) -?
2H2S + 3O2 = 2H2O + 2SO2, – we solve the problem, relying on the composed reaction equation:
1) Find the amount of hydrogen sulfide that has reacted:
n (H2S) = m: M = 68 g: 34 g / mol = 2 mol
2) We compose a logical expression:
If 2 mol H2S gives 2 mol SO2,
then 2 moles of H2S will give x moles of SO2, is a tautology, but sometimes calculations lead to such results.
then x = 2 mol.
3) Find the mass of sulfur oxide released during the reaction:
m (SO2) = n * M = 2 mol * 64 g / mol = 128 g
4) find the volume of sulfur oxide:
V (SO2) = n * Vm = 2 mol * 22.4 l / mol = 44.8 l.
Answer: m (SO2) = 128 g; V (SO2) = 44.8 liters.
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